Question 74788
{{{(x^2-3)(x^2+3x-4)=0}}}
{{{(x^2-3)=0}}}Set each factor equal to zero
{{{x=0+-sqrt(3)}}}There's one set of roots
{{{(x^2+3x-4)=0}}}
{{{(x+4)(x-1)=0}}}Factor the right side
{{{x+4=0}}}
{{{x=-4}}}
{{{x-1=0}}}
{{{x=1}}}
So the roots are 
{{{x=1}}}, {{{x=-4}}}, {{{x=sqrt(3)}}} and {{{x=-sqrt(3)}}}. Since this is a 4th degree polynomial, we have found all the roots and they are all real roots.