Question 74758
{{{0.25^x+cross(-0.5+0.5)=2+0.5}}} Add 0.5 to both sides
{{{log(0.25^x)=log(2.5)}}}Take the log base 0.25 of both sides
{{{x=log(2.5)}}}
{{{x=log(2.5)/log(0.25)}}}
{{{x=-0.66096}}}
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Check:
{{{0.25^(-0.66096)-0.5=2}}}
{{{2.4999-.5=2}}}
{{{1.9999=2}}} which is really close and it's only off due to roundoff errors so it works