Question 888362
9z^2 +48z +64 = x^2, where x is the length of a side of the square
factor the polynomial
(3z+8)^2 = x^2
take square root of both sides of =
x = 3z +8
therefore side of square x = 3z +8
now the perimeter(P) of the square is
P = 4*(3z+8) = 12z +32