Question 888258
This is a quadratic series whose members are given as
     2   6   12   20   30 ......4054182
     1   2    3    4    5        2013
n^2  1   4    9   16   25       4052169
a member in the geometric sequence is given by
nth term = n^2 +n
now we know that the summation of n^2 = n[n+1][2n+1]/6 and
summation of n is n(n+1)/2
therefore the sum(S) of the series is
S = 2013(2014)(2*2013+1)/6 + 2013(2014)/2
S = 16326190914/6 + 4054182/2
S = 2721031819 +  2027091
S = 2723058910