Question 888190
Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list. Round your answers to three decimal places where appropriate.)
−sin 2θ − cos 4θ = 0
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{{{-sin(2theta)-cos(4theta)=0}}}
{{{-sin(2theta)-(1-2sin^2(2theta))=0}}}
{{{-sin(2theta)-1+2sin^2(2theta)=0}}}
{{{2sin^2(2theta)-sin(2theta)-1=0}}}
{{{(2sin(2theta)+1)(sin(2theta)-1)=0}}}
..
{{{2sin(2theta)+1=0}}}
{{{sin(2theta)=-1/2}}}
2theta=7π/6, 11π/6
theta=7π/12, 11π/12
or
{{{sin(2theta)-1=0}}}
{{{sin(2theta)=1}}}
{{{2theta=pi/2}}}
{{{theta=pi/4}}}