Question 74741

Let x=amount of water that must be added

Now we know that he amount of pure salt before adding the water must equal the amount of pure salt after adding the water.  So our equation to solve is:

0.10(48)=0.06(48+x)  get rid of the parens

4.8=2.88+0.06x  subtract 2.88 from both sides

4.8-2.88=2.88-2.88+0.06x  collect like terms
1.92=0.06x  divide both sides by 0.06x

x=32 gal of water must be added


CK
0.10(48)=0.06(48+32)
4.8=0.06(80)
4.8=4.8



Hope this helps----ptaylor