Question 74737
{{{sqrt(3)*(8+2*sqrt(3))}}}
{{{sqrt(3)*8+2*sqrt(3)*sqrt(3)}}}Distribute the sqrt(3) to each term
{{{8*sqrt(3)+2*sqrt(3*3)}}}Rewrite the product of square roots as a square root of a product (ie {{{sqrt(x)sqrt(y)=sqrt(xy)}}}) so {{{sqrt(3)*sqrt(3)=sqrt(3*3)}}}
{{{8*sqrt(3)+2*sqrt(9)}}}
{{{8*sqrt(3)+2*(3)}}}
{{{8*sqrt(3)+6}}} There's the simplified form