<PRE><B>Question 887984</B>
a positive number is divided into two parts such that the sum of the squares of the two parts is 20.
x^2 + y^2 = 20
:
 the square of the larger part is 8 times the smaller part.
y^2 = 8x
:
 taking x as the smaller part of the two parts, find the number
In the 1st equation replace y^2 with 8x
x^2 + 8x = 20
x^2 + 8x - 20 = 0
Factors to
(x-2)(x+10) = 0
the positive solution
x = 2, 
therefore
y = {{{sqrt(8*2)}}}
y = 4
:
4 and 2 are the two numbers
:
:
Check: 4^2 + 2^2 = 20</PRE>