Question 887955
{{{x/9= 4/y= y/36}}}

{{{36y(x/9= 4/y= y/36)}}}

{{{4xy=4*36=y^2}}}

{{{4xy=highlight_green(3)*36}}} and {{{4*36=y^2}}}

The first one is {{{xy=27}}} and the second one is {{{highlight(y=12)}}}; so the first one is x=27/y=27/12, {{{highlight(x=9/4)}}}.  Seems strange.

Maybe a mistake, maybe not.  (I found the mistake, outlined in  {{{highlight_green(green)}}}).


Try differently.  Split the three members from the original equation.

{{{x/9=4/y}}}
{{{xy=36}}}
-
{{{4/y=y/36}}}
{{{y^2=4*36}}}
{{{y=2*6}}}
{{{highlight(y=12)}}}
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Now back to the first equation again.
{{{xy=36}}}
{{{x=36/y}}}
{{{x=36/12}}}
{{{highlight(x=3)}}}
-
This second solution seems better.  You can search for any mistake I must have made in the first method.


CHECK THIS LAST SET OF RESULTS:
{{{3/9=4/12=12/36}}}
{{{1/3=1/3=1/3}}}---Yes, looks good.
-
x=3, y=12