Question 887783
Solve the following systems graphically. 0
-x+3y=8 and x+y=2
:
Write both equation in the y = mx + b, slope intercept form,
-x + 3y = 8
add x to both sides
3y = x + 8
y has to have a coefficient of 1, divide both sides by 3
y = {{{1/3}}}x + {{{8/3}}}
:
x + y = 2
subtract x from both sides
y = -x + 2
:
Choose value for x and find y, make a table for each, I choose -2, +1 and +4
y = {{{1/3}}}x + {{{8/3}}}
 x | y
-------
-2 |+2
+1 |+3
+4 | 4
Same for y = -x + 2
 x | y
--------
-2 |+4
+1 |+1
+4 |-2
:
Plot these two graphs, should look like this
{{{ graph( 300, 200, -6, 6, -6, 6, (1/3)x+(8/3), -x+2) }}}
Red is the 1st equation, green is the 2nd
The solution is where they intersect at x=-.5, y=+2.5