<PRE><B>Question 887760</B>
two cyclists start at the same point and travel in opposite directions. one cyclist travels 9 km/h slower than the other. if the two cyclists are 99 km apart after 3 hours what is the rate of each cyclist?
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let x=rate of slower cyclist
x+9=rate of faster cyclist
distance=travel time*rate
..
3x+3(x+9)=99
3x+3x+27=99
6x=72
x=12
x+9=21
rate of slower cyclist=12 km/h
rate of faster cyclist=21 km/hr</PRE>