Question 887704
To rationalize the denominator, multiply top and bottom of the fraction by {{{sqrt(125x)}}} to get


{{{4/(sqrt(125x))}}}


{{{(4*sqrt(125x))/(sqrt(125x)*sqrt(125x))}}}


{{{(4*sqrt(125x))/((sqrt(125x))^2)}}}


{{{(4*sqrt(125x))/(125x)}}}


{{{(4*sqrt(25*5x))/(125x)}}}


{{{(4*sqrt(25)*sqrt(5x))/(125x)}}}


{{{(4*5*sqrt(5x))/(125x)}}}


{{{(4*5*sqrt(5x))/(5*25x)}}}


{{{(4*cross(5)*sqrt(5x))/(cross(5)*25x)}}}


{{{(4*sqrt(5x))/(25x)}}}


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After rationalizing the denominator, we go from {{{4/(sqrt(125x))}}} to {{{(4*sqrt(5x))/(25x)}}}