Question 887433
Solve 4x^2-20x-3=0 by completing the square.
4x^2-20x-3=0
4x^2-20x = 3
{{{x^2 - 5x = 3/4}}}
{{{x^2 - 5x + (-5/2)^2 = 3/4 + (-5/2)^2}}}
{{{(x - 5/2)^2 = 7}}}
That's how it's done.