Question 887420
Find the equation of the tangent line to y=3x^2+0.6x-3 at x=1.5
y=3x^2+0.6x-3
@x = 1.5, y = 4.65 --> tangent at (1.5,4.65)
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y' = 6x + 0.6
@x = 1.5, y' = 9.6
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y - 4.65 = 9.6*(x - 1.5)