Question 10074
Simplify:

{{{(6^3)(6^-5)(x^7)(x^-3)}}}

Remember:  {{{(x^a)(x^b) = x^(a+b)}}} and: {{{x^(-a) = 1/x^a}}}

So, you can write:

{{{(6^(3-5))(x^(7-3))}}}

{{{(6^-2)(x^4)}}}

{{{(1/6^2)(x^4)}}}

{{{(x^4)/36}}}