Question 74682
y = 2x^2 - 10x + 27 
This is the equation of a parabola opening up.
2(x^2-5x+(5/2)^2) = y - 27 + 2*(25/4)
2(x-(5/2))^2 = y-58/4
2(x-(5/2))^2 = y-29/2
(x-(5/2))^2 = (1/2)(y-29/2)
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4p=1/2 ; p=1/8
Vertex at (5/2,29/2)
Focus at (5/2, 29/2 + 1/8) = (5/2, 117/8)
Directrix: y=29/2 - 1/8 ; y=115/8
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{{{graph(400,300,-10,10,-10,30,2x^2-10x+27)}}}
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Cheers,
Stan H.