Question 887296
{cuberoot(128x^5)}

I took the cube root and factored the 128 to get 2*64x^5
a 4 is pulled out and 2 is left in the cubed root.
Im not sure what to do about the x^5 in the cubed root.
I think you pull out x^5 and get a finished product of:
(4x^5){cube root(2)}

Would this be correct? Thanks for the help!
<pre>
You need to break up the RADICAND into CUBES.
{{{x^5 = x^3*x^2}}}, so:
{{{root(3, 128x^5)}}} becomes: {{{root(3, 4^3*2*x^3x^2)}}}
{{{root(3, 4^3*x^3*2x^2)}}} ------ Rearranging radicand
{{{highlight_green(highlight_green(4x*root(3, 2x^2)))}}} ----- Taking out 4 & x