Question 887179
Parentheses Added for the Numerator.


Just form the expression and simplify!


{{{(2(a+h)^2+3(a+h)-1-(2a^2+3a-1))/h}}}, which is only simple substituting.  Working into that,
{{{(2(a^2+2ah+h^2)+3a+3h-1-2a^2-3a+1)/h}}}
{{{(2a^2+4ah+2h^2+3a+3h-2a^2-3a)/h}}}
{{{(4ah+2h^2+3a+3h-3a)/h}}}
{{{(4ah+2h^2+3h)/h}}}
{{{highlight(4a+2h+3)}}}





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Much later, you will be interested in what happens to the final expression as h approaches 0.  The result would be that the difference quotient approaches {{{4a+3}}}.