Question 74613
substitution method
-x+3y=10----------------------eq 1
2x+8y=-6-------------------------eq2

solve for x in eq 1 and plug the value for x into eq 2:

-x+3y=10  subtract 3y from both sides

-x+3y-3y=10-3y
-x=10-3y  multiply both sides by -1
x=3y-10   plug this into eq2

2(3y-10)+8y=-6  get rid of parens

6y-20+8y=-6  add 20 to both sides and collect like terms
14y-20+20=-6+20
14y=14  divide both sides by 14
y=1   substitute y=1 into eq 2-----------------------------ans for y
2x+8(1)=-6
2x+8=-6 subtract 8 from both sides
2x+8-8=-6-8 collect like terms
2x=-14  divide both sides by 2
x=-7---------------------------------------------ans for x

CK
-x+3y=10----------------------eq 1
7+3=10
10=10

2x+8y=-6-------------------------eq2
2*(-7)+8=-6
-14+8=-6
-6=-6



Hope this helps-----ptaylor