Question 887128
I.	Given the following polynomial:  2x^2+7x-15=0 .  Check all that apply.

	The value of the discriminant is 169.
	There are 2 real roots.
	There are 2 irrational roots.
	The graph intersects the y-axis twice.
	The parabola is directed upward.
	The axis of symmetry is located at  x=-7/4
	The vertex is located at:   (-7/4, -49/8)
	The roots are:  (5,3/2)
	The graph intersects the y axis at (0, -15).
	The graph intersects the x-axis at (-5, 0) and (1.5, 0)

HELP PLEASE
<pre>
{{{2x^2 + 7x - 15 = 0}}}, or
{{{0 = 2x^2 + 7x - 15}}}
{{{y = ax^2 + bx + c}}} 

&#61600;  The value of the discriminant is 169. Discriminant: {{{b^2 - 4ac}}}, or {{{7^2 - 4(2)(-15)}}}___49 + 120 = 169 (CHECK)   
&#61600;  There are 2 real roots. Since the value of DISCRIMINANT (169) > 0, then there are 2 REAL roots. (CHECK)
&#61600;  There are 2 irrational roots. Since the value of the DISCRIMINANT (169) is a perfect square ({{{13^2}}}), roots
   are RATIONAL (NO CHECK)
&#61600;  The graph intersects the y-axis twice. Substituting 0 for x in {{{2x^2 + 7x - 15}}} results in y being – 15. The
   graph has a sole y-intercept, at – 15 (NO CHECK)
&#61600;  The parabola is directed upward. Since a > 0, the parabola opens upwards. (CHECK)
&#61600;  The axis of symmetry is located at x = {{{- 7/4}}}. Axis of symmetry is at {{{x = - b/2a}}}, or {{{x = - 7/(2*2)}}}, or {{{- 7/4}}} (CHECK)  
&#61600;  The vertex is located at: ({{{- 7/4}}}, {{{- 49/8}}}). Substituting {{{- 7/4}}} for x in {{{2x^2 + 7x - 15}}} produces: {{{2(- 7/4)^2 + 7(- 7/4) - 15}}}, 
   or {{{2(49/16) - 49/4) - 15}}}, or {{{49/8 - 49/4 - 15}}}, or {{{49/8 - 98/8 - 120/8}}}, or {{{- 169/8}}} (NO CHECK) 
&#61600;  The roots are: (5,3/2)____{{{2x^2 + 7x - 15 = 0}}} factors to (2x - 3)(x + 5) = 0, so roots are: {{{x = 3/2}}} and {{{x = - 5}}} (NO CHECK)
&#61600;  The graph intersects the y axis at (0, -15). The y-intercept was found to be – 15, so y-intercept is (0, - 15). 
   This is a CHECK. 
&#61600;  The graph intersects the x-axis at (-5, 0) and (1.5, 0). As seen above, roots are {{{(3/2)_and_- 5}}}, so the graph
   intersects the x-axis at ({{{3/2}}}, {{{0}}}) and ({{{- 5}}}, {{{0}}}). This is a CHECK.