Question 886968
What is the general form of the equation of a circle with center at (a,b) and radius of length m?
(x-a)^2 + (y-b)^2 = m^2
x^2-2ax+a^2 + y^2-2by+b^2-m^2 = 0
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Ans:: A
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Cheers,
Stan H.
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A.x^2+y^2-2ax-2by+(a^2+b^2-m^2)=0
 B.x^2+y^2+2ax+2by+(a^2+b^2-m^2)=0
 C.x^2+y^2-2ax-2by+(a+b-m^2)=0
 D.x^2+y^2+2ax+2by+a^2+b^2=-m^2