Question 886877
let x be the side of the square, then
(x+4)*(x+3) = 110
x^2 +7x +12 = 110
x^2 +7x -98 = 0
1) can not use extracting the square root since polynomial is not a perfect square.
2) (x+14)*(x-7) = 0
x = -14 or 7
we need a positive value solution so we reject x = -14
the length of the side of the square is 7 units
3) x^2 +7x = 98
x^2 +7x + 49/4 = 98 + 49/4
(x + 7/2)^2 = 392/4 + 49/4 = 441/4
take square root of both sides of =
3.1) x + 7/2 = 21/2
x = 14/2 = 7
3.2) x +7/2 = -21/2
x = -28/2 = -14
4) x^2 +7x -98 = 0
x = (-b + or - square root(b^2 -4ac))/ (2a)
4.1) x = (-7 + square root(49 - 4*1*(-98))) / 2 = 7
4.2) x = (-7 - square root(49 - 4*1*(-98))) / 2 = -14