Question 886821
Three numbers are chosen at random without replacement from the set {0, 1, 2, 3, ... , 10}. Calculate the probabilities that for the three numbers drawn

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what the probabilities that the sum is equal to 7
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The only combinations that sum to 7 are these 4:

0+1+6 = 7
0+2+5 = 7
0+3+4 = 7
1+2+4 = 7

The number of combinations of 3 numbers are C(11,3) = 165

Answer {{{4/165}}}

Edwin</pre>