Question 74582
The graph y=abs(x) forms a "v" pointing downward with the point located at the origin (0,0). The open angle of the "v" is a right angle.


The radii of the circle tangent to both branches of the "v" intersect the branches of the "v" at right angles and form a square with the center of the circle at the corner of the square diagonally opposite the origin.


For a circle of radius 4, forming a square of side 4, the length of the diagonal is {{{4*sqrt(2)}}}


Using the general equation for a circle with radius 4 centered at (0,{{{4*sqrt(2)}}}) gives:


{{{(x-0)^2+(y-(4*sqrt(2)))^2=4^2}}}