Question 886707
To find {{{g(a+1)}}}, we just plug in {{{x = a+1}}}. That means you replace EVERY copy of x with 'a+1' and simplify.



{{{g(x)=2x+1}}} Start with the given function


{{{g(x)=2(x)+1}}} This step is optional, but it helps to have every 'x' on the right side in parenthesis.


{{{g(a+1)=2(a+1)+1}}} Everywhere you see an {{{x}}}, replace it with {{{a+1}}}


{{{g(a+1)=2a+2*1+1}}} Distribute


{{{g(a+1)=2a+2+1}}} Multiply


{{{g(a+1)=2a+3}}} Combine like terms.



And we're done. The final answer is {{{g(a+1)=2a+3}}}