Question 886570
The center of an ellipse is the point (-4, 2) and one vertex is at (1, 2). The length of each latus rectum is 4. Find the eccentricity.
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Given data shows ellipse has a horizontal major axis.
Its standard form of equation: {{{(x-h)^2/a^2+(y-k)^2/b^2}}},a>b, (h,k)=coordinates of center
1/2 length of major axis=5 (center to vertex)
a=5
a^2=25
latus rectum=2b^2/a=4
4a=2b^2
b^2=2a=10
c^2=a^2-b^2=25-10=15
c=√15
eccentricity=c/a=√15/5