Question 886388
One hose can fill a pool 2.25 (9/4) times faster than another hose can. When both hoses are used, they fill the pool in 10 hours. How long would it take to fill the pool if only the faster hose is used?
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Faster hose DATA:
time = x hrs/job ; rate = 1/x job/hr
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Slower hose DATA:
time = (9/4)x hrs/job ; rate = (4/9x) job/hr
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Together DATA:
time = 10 hrs/job; rate = 1/10 job/hr
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Equation:
rate + rate = together rate
1/x + (4/(9x)) = 1/10
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Multiply thru by 90x to get:
90 + 40 = 9x
9x = 130
x = 130/9 = 14.4 hrs (time for faster hose)
(9/4)x = 32.5 hrs (time for slower hose)
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You are correct.
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Cheers,
Stan H.
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