Question 74559
6x^2-x-1/2x^+x-1 * x^2-1/x^2-2x+1
My answer is (3x+1)(x+1)/ (1x+1)(x-1)
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Factor to get:
=[(2x-1)(3x+1)/(2x-1)(x+1)]([(x+1)(x-1)/(x-1)(x-1)]

Cancel factors common to numerator and denominator, such as 
(2x-1),(x+1),(x-1)
What is left is:

=(3x+1)/(x-1)
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Cheers,
Stan H.