Question 9992
You can use the formula: d = rt  Distance = rate X time.

Let's do the calculation for the outbound leg first.

{{{d1 = (r1)(t1)}}}
{{{d1 = 6 mph(t1)}}}

Now the inbound leg:

{{{d2 = (r2)(t2)}}}
{{{d2 = 8 mph(t2)}}}

Ok, we know that the outbound distance (d1) is the same as the as the inbound distance (d2).
We also know that the total time (t1 + t2) is 7 hours. We can write this as:
{{{t1 = 7 - t2}}}

Now, setting d1 = d2 and substituting (7-t2) for t1, we can write:

{{{6 mph(7-t2) = 8 mph(t2)}}} Simplify and solve for t2
{{{42 - 6(t2) = 8(t2)}}} Add 6(t2) to both sides.
{{{42 = 14(t2)}}} Divide both sides by 14.
{{{t2 = 3 hrs}}}

But, we need the distance, d1 or d2 (they are the same). Let's find d2.

{{{d2 = (r2)(t2)}}}
{{{d2 = 8 mph(3 hrs)}}}
{{{d2 = 24 miles}}}

The distance to the club house is 24 miles