Question 74591
find the sum 1 + 2/3 + 4/9 + 8/27 + ... + 64/729.
The last term is (2/3)^6 and it is the 7th terms because the
series begins with (2/3)^0.
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The sum is S(7) = [(2/3)^8 -1]/[(2/3)-1) = 2.8829....
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Cheers,
Stan H.