Question 886121
Reacting with water in an acidic solution at a particular temperature, compound A decomposes into compounds B and C according to the law of uninhibited decay. An initial amount of 0.60 M of compound A decomposes to 0.55 M in 30 minutes. How much of compound A will remain after 2 hours? .42 is the answer I came up for on this part.
Model:: y = ab^x
0.55 = 0.6*b^(1/2)
sqrt(b) = 0.9167
b = 0.8403
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Equation:
y = 0.6*0.8403^x
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Your Problem
y = 0.6*(0.8403)^2
y = 0.4236
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 How long will it take until 0.10 M of compound A remains?
0.10 = 0.6*0.8403^x
0.8403^x = 0.167
x = ln(0.167)/ln(0.8403) = 10.29 hours
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Cheers,
Stan H.
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