Question 74592
Five fair coins are tossed. Find the probability of obtaining 4 heads and 
1 tail.
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The result for each coin is independent of the result for each other coin.
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P(H)=1/2 ; P(T)=1/2
The result you are looking for can be 
THHHH
HTHHH
HHTHH
HHHTH
HHHHT
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These are "mutually exclusive" events and each has probability (1/32)^5=1/32
Because these events are mutually exclusive you add the probabilities to get:
P(4 heads and a tail) = 5(1/2)^5 =5/32
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Cheers,
Stan H.