Question 885947
{{{ log( 2^10 ) }}}
This is {{{ log( 2*2*2*2*2*2*2*2*2*2 ) }}}
And this equals {{{ log(2) + log(2) + log(2) }}} 10 additions
And this gives the result
{{{ log( 2^10 ) = 10*log(2) }}}
which follows the general rule:
{{{ log( a^b ) = b*log( a ) }}}