Question 885780
That would not be what you want to use.    {{{6/2a}} by itself should be the same as {{{(6/2)*a=3a}}}; but you ask for help on "performing the division" of all that longer expression.


You might really be asking for this:  {{{(6a^3-4a^2+6)/(2a)}}}.
Remember your fraction arithmetic skills and find the expression is {{{6a^3/(2a)-4a^2/(2a)+6/(2a)}}}


{{{highlight(3a^2-2a+3/a)}}}.