Question 885897
The first, second and third scores, x, y, z, respectively.


{{{(x+y+z)/3=85}}}.


 <i>Her second exam score was 5 points better than her first, and her third exam score was 5 points better than her second exam.</i>
{{{y=x+5}}} and {{{z=y+5}}}.


A few different ways to go.


The last two equations:  {{{x=y-5}}} and {{{z=y+5}}};  substitute into the average85 equation:
{{{((y-5)+y+(y+5))/3=85}}}
{{{(y-5+y+y+5)/3=85}}}
{{{(3y)/3=85}}}
{{{highlight(y=85)}}}----ONE of the scores, the second score.
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{{{highlight(x=80)}}} and {{{highlight(z=90)}}}.