Question 885820
Joe’s rectangular backyard has an area of 3,100 ft 2. If the length of his yard is 12 ft more than the width, what are the dimensions of his yard?
***
let x=width
x+12=length
length*width=area
..
x(x+12)=3100
x^2+12x-3100=0
(x-50)(x+62)=0
x=-62 (reject)
or
x=50
x+12=62
dimensions of his yard:50 ft by 62 ft