Question 74574
Start by finding the factors of the constant 4. They are +/-[1,2,4]

So, divide the cubic by (x-1),(x+1),(x-2),(x+2),(x-4),(x+4). Upon division, does any of these cause the cubic to reduce to a quadratic?. 
Yes, (x-2) and (x-1).

{{{(x^3-5x^2+8x-4)/(x-2)=x^2-3x+2}}}

So, x-2 is a factor.

Next, factor the resulting quadratic. That's easy.

{{{x^2-3x+2=(x-2)(x-1)}}}

So, the factored form of the cubic is {{{(x-2)^2(x-1)}}}