Question 885781
Standard form  {{{y=a(x-h)^2+k}}}.
Vertex is (h,k)=(-2,5);
{{{y=a(x-(-2))^2+5}}}
{{{y=a(x+2)^2+5}}};
You want to use the other point to find a.
{{{a(x+2)^2=y-5}}}
{{{a=(y-5)/(x+2)^2}}}
{{{a=(9-5)/(0+2)^2}}}
{{{a=4/4=1}}}
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RESULT:  {{{highlight(y=(x+2)^2+5)}}}, and the a=1 is implied or understood.