Question 885698
A plane flies 300 miles having a tail wind of 10 mph and returns against a tail wind of 20 mph. Find the speed of the plane in still air if the time of the flight is 4.5 hours.
***
let x=speed of plane in still air
(x+10)=speed of plane with tail wind
(x-20)=speed of plane against the wind
travel time=distance/speed
{{{300/(x+10)+300/(x-20)=4.5}}}
300(x-20)+300(x+10)=4.5(x-20)(x+10)
300x-6000+300x+3000=4.5(x^2-10x-200)
600x-3000=4.5x^2-45x-900
4.5x^2-645x+2100=0
solve for x by quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=4.5, b=-645, c=2100
ans:
x=3.33 (reject)
or
x=140
speed of plane in still air=140 mph