Question 885609
how many milliliters of pure acid must be added to 150 milliliters of a 60% solution of add to obtain a 70% solution?
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let x=amt of pure acid to add
..
100%x+60%*150=70%(x+150)
x+90=.70x+105
0.30x=15
x=50
amt of pure acid to add=50 mm