Question 885506
the diagonal of a rectangle is 36cm long. 
if the rectangle is twice as long as it is wide find the width of the rectangle
:
Let x = the width
then
(2x) = the length
:
Using pythag: a^2 + b^2 = c^2, where
a = x
b = (2x)
c = 36
:
x^2 + (2x)^2 = 36^2
x^2 + 4x^2 = 1296
5x^2 = 1296
x^2 = 1296/5
x^2 = 259.2
x = {{{sqrt(259.2)}}}
x = 16.1 is the width
:
:
You can check this for yourself: does 16.1^2 + 32.2^2 = 36^2?