Question 885527
{{{x^8-1}}}
{{{(x^4+1)(x^4-1)}}}
{{{(x^4+1)(x^2+1)(x^2-1)}}}
{{{(x^4+1)(x^2+1)(x+1)(x-1)}}}


That divided by (x-1) will be the same as {{{(x^4+1)(x^2+1)(x+1)}}} which you can also find using polynomial division or using synthetic division.    Either of those way,s the dividend must be used as {{{x^8+0*x^7+0*x^6+etcetera+0x^1-1}}}.