Question 885592
List of the three consecutive odd integers:
2x+1
2x+3
2x+5.


Difference between first and third:  {{{(2x+5)-(2x+1)=4}}}.


Product of first and second, plus square of the second: {{{(2x+1)(2x+3)+(2x+3)^2}}}


They are given as equal:  {{{highlight_green((2x+1)(2x+3)+(2x+3)^2=4)}}}



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I see now your hint of "let x be the first integer"; but I followed a more typical method.  I used x as any positive whole integer, and then built the consecutive ODD integers based on this idea.  2x will be an EVEN number, but 2x plus an ODD number will be an ODD number.
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Now, when you solve for x, this will not be your first integer of the list.  Your first integer of the list will be {{{2x+1}}}.