Question 885509
<pre>
There are 5 vowels and 21 consonants. (We are considering Y as a consonant).

There are C(26,2) = 325 possible pairs of letters.
There are C(5,2) = 10 unsuccessful pairs of letters (two vowels)
Therefore there are 325-10 = 315 successful pairs of letters.

Probability: 315 successful pairs out of 325 possible pairs or {{{315/325}}},
which reduces to {{{63/65}}}.

Edwin</pre>