Question 885488
4 gals of pure iodine are added to 46 gals of 2% iodine. How much of the final solution do you have? How much iodine is contained in the mixture? What is the strength (percentage) of iodine in the mixture.
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let x=strength (percentage) of iodine in the mixture.
100%*4+2%*46=x*(46+4)
4+0.92=50x
x=4.092/50
x=.0984
strength (percentage) of iodine in the mixture=9.84%