Question 885372
$6300 is invested, part of it at 10% and part of it at 8%. For a certain year, the total yield is $566.00. How much was invested at each rate? 
How much was invested at 10%? 
How much was invested at 8%?
solution 
let $ X at 10% and Rs $6300-x at 8%

X(10)/100 +(6300-x)8/100 =$566.00 by  LCM
10X -8x +50400/100 =566
10x-8x +50400 = 56600
2x =56600-50400 =  6200
x=6200/2 = $3100
other 6300-3100 = $3200
answer  $3100 at 10%
        $3200 at  8%