Question 885345
{{{system(kx+3y=3,12x+ky=6)}}}
The system of equations  has no solution when
{{{k/12=3/k}}} 
{{{k^2=12*3}}}
{{{k^2=36}}}
{{{k[1]=-6}}}, {{{k[2]=6}}}
Answer: {{{k[1]=-6}}}, {{{k[2]=6}}}