Question 885233
i believe this is going to be 2/13 * 1/12
on the first draw, it could be either one of the 2.
on the second draw it can only be the other one of the 2.
total probability should be 2/(13*12) = 1/(13*6) = 1/78.


another way to look at it is:
total number of ways you can pick any 2 out of 13 is equal to 13C2 = 78
total number of ways you can get the twins is 2C2 = 1.
probability is therefore 1/78.