Question 885300
mean = 78
standard deviation = 7.6
with a score of 85, the z score would be:
(85 - 78) / 7.6 = .92
from the z-score table, a z score of .92 will have .8212 of the area under the distribution curve to the left of it.
this means that a z score of .92 will have 100 - .8212 = .1788 of the area under the distribution curve to the right it it.
this means that the probability that the student scored higher than 85 is .1788.
the z-score table i used is shown below:
<a href = "http://lilt.ilstu.edu/dasacke/eco148/ztable.htm" target = "_blank">http://lilt.ilstu.edu/dasacke/eco148/ztable.htm</>
the z score was  rounded to 2 decimal places to conform to the capabilities of the z score table.