Question 885311
n = 3
p = 3/7
q = 1-p = 4/7
p(x) = nCx * p^x * q^(n-x)
when x = 3 and n = 3 and p = 3/7 and q = 4/7, this becomes:
p(3) = 3C3 * (3/7)^3 * (4/7)^0 = .078717201
all possible probabilities are shown below:
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